Adam has half the money in his right pocket than in his left pocket. If he transferred 40 crowns from the left pocket to the right, he would have the same in both pockets. Calculate how many crowns does Adam have in his left pocket more than in his right? How many crowns does Adam have in both pockets in total?

Result

x =  80
y =  240

#### Solution:

$\ \\ p=l-l/2 \ \\ l-40=p+40 \ \\ \ \\ l-2p=0 \ \\ l-p=80 \ \\ \ \\ l=160 \ \\ x=p=80 \ \\ x=l-p=160-80=80$
$y=l+p=160+80=240$

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