# The piglet

The weight of the piglet grew regularly by five kilograms for four months. Determine the proportion by weight of the piglet in each month, if the first weighed 35 kg.

Result

r1 =  8:7
r2 =  9:8
r3 =  10:9
r4 =  11:10

#### Solution:

$m_{0}=35 \ \text{kg} \ \\ d=5 \ \text{kg} \ \\ m_{1}=m_{0}+d=35+5=40 \ \text{kg} \ \\ \ \\ r_{1}=m_{1}/m_{0}=40/35 \doteq \dfrac{ 8 }{ 7 } \doteq 1.1429≈ 1.1429 \doteq 8:7$
$m_{2}=m_{1}+d=40+5=45 \ \text{kg} \ \\ r_{2}=m_{2}/m_{1}=45/40=\dfrac{ 9 }{ 8 }=1.125=9:8$
$m_{3}=m_{2}+d=45+5=50 \ \text{kg} \ \\ r_{3}=m_{3}/m_{2}=50/45 \doteq \dfrac{ 10 }{ 9 } \doteq 1.1111≈ 1.1111 \doteq 10:9$
$m_{4}=m_{3}+d=50+5=55 \ \text{kg} \ \\ r_{4}=m_{4}/m_{3}=55/50=\dfrac{ 11 }{ 10 }=1.1=11:10$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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