Telegraph poles

The bases of two adjacent telegraph poles have a height difference of 10.5 m. How long do the wires connect the two poles if the slope is 39° 30´?

Correct result:

x =  16.507 m

Solution:

h=10.5 m A=39+30/60=792=39.5   sinA=h:x x=h/sinA=h/sin39.5 =10.5/sin39.5 =10.5/0.636078=16.507 mh=10.5 \ \text{m} \ \\ A=39 + 30/60=\dfrac{ 79 }{ 2 }=39.5 \ ^\circ \ \\ \ \\ \sin A=h:x \ \\ x=h/\sin A ^\circ =h/\sin 39.5^\circ \ =10.5/\sin 39.5^\circ \ =10.5/0.636078=16.507 \ \text{m}



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