# Dices throws

What is the probability that the two throws of the dice:

a) Six falls even once
b) Six will fall at least once

Result

p1 =  0.694
p2 =  0.306

#### Solution:

$q_{1}=\dfrac{ 1 }{ 6 } \doteq 0.1667 \ \\ q_{2}=1 - q_{1}=1 - 0.1667 \doteq \dfrac{ 5 }{ 6 } \doteq 0.8333 \ \\ p_{1}=q_{2}^2=0.8333^2 \doteq \dfrac{ 25 }{ 36 } \doteq 0.6944 \doteq 0.694$
$p_{2}=q_{1} + q_{1} -q_{1} \cdot \ q_{1}=0.306$

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