# In the

In the rectangle ABCD, the distance of its center from the line AB is 3 cm greater than from the line BC. The circumference of the rectangle is 52 cm. Calculate the contents of the rectangle. Express the result in cm2.

Correct result:

S =  160 cm2

#### Solution:

$o=52 \ \text{cm} \ \\ \ \\ \ \\ o=2 \cdot \ (a+b) \ \\ b/2=3 + a/2 \ \\ 52=2 \cdot \ (a+b) \ \\ b/2=3 + a/2 \ \\ \ \\ 2a+2b=52 \ \\ a-b=-6 \ \\ \ \\ a=10 \ \\ b=16 \ \\ \ \\ \ \\ S=a \cdot \ b=10 \cdot \ 16=160 \ \text{cm}^2$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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