On a line

On a line p : 3 x - 4 y - 3 = 0, determine the point C equidistant from points A[4, 4] and B[7, 1].

Correct answer:

x =  9
y =  6

Step-by-step explanation:

3x4y3=0  x = (3+4y)/3 y = (3x3)/4 AC = BC  (x4)2+(y4)2 = (x7)2+(y1)2  (x4)2+((3x3)/44)2=(x7)2+((3x3)/41)2 1.5x=13.5 23x=227 3x=27 x=27/3=9

(x-4)^2+((3x-3)/4-4)^2 = (x-7)^2+((3x-3)/4-1)^2


(x-4)^2+((3·x-3)/4-4)^2 = (x-7)^2+((3·x-3)/4-1)^2

6x = 54


x = 54/6 = 9

x = 9

Our simple equation calculator calculates it.
y=(3x3)/4=(3 93)/4=6



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