Intersections 3

Find the intersections of the circles x2 + y2 + 6 x - 10 y + 9 = 0 and x2 + y2 + 18 x + 4 y + 21 = 0

Correct answer:

x1 =  -1.3335
y1 =  0.2859
x2 =  -7.9135
y2 =  5.9259

Step-by-step explanation:

x2 + y2 + 6 x  10 y + 9 = 0 x2 + y2 + 18 x + 4 y + 21 = 0  e2e1: (186)x + (4+10)y + (219) = 0 y = 6/7 (x + 1)  x2+(6/7(x+1))2+6x10(6/7(x+1))+9=0  x2+(6/7(x+1))2+6 x10(6/7(x+1))+9=0 1.734693877551x2+16.041x+18.306=0  a=1.734694;b=16.041;c=18.306 D=b24ac=16.041241.73469418.306=130.2857142857 D>0  x1,2=2ab±D=3.46938816.04±130.29 x1,2=4.623529±3.289997 x1=1.333531989=1.3335 x2=7.913526835

Our quadratic equation calculator calculates it.

y1=6/7 (x1+1)=6/7 ((1.3335)+1)=0.2859
y2=6/7 (x2+1)=6/7 ((7.9135)+1)=5.9259



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