Quadrilateral pyramid

A regular quadrilateral pyramid has a volume of 24 dm3 and a base edge a = 4 dm.
Calculate:
a/height of the pyramid
b/sidewall height
c/surface of the pyramid

Correct result:

h =  4.5 dm
h2 =  4.9244 dm
S =  55.3954 dm2

Solution:

V=24 dm3 a=4 dm  S1=a2=42=16 dm2  V=13S1 h  h=3 VS1=3 2416=92=92 dm=4.5 dm
h2=h2+(a/2)2=4.52+(4/2)2=4.9244 dm
S2=a h22=4 4.92442=97 dm29.8489 dm2  S=S1+4 S2=16+4 9.8489=55.3954 dm2



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