Quadrilateral pyramid

In a regular quadrilateral pyramid, the height is 6.5 cm and the angle between the base and the side wall is 42°. Calculate the surface area and volume of the body. Round calculations to 1 decimal place.

Correct result:

S =  273 cm2
V =  225.8 cm3

Solution:

h=6.5 cm A=42   tanA=h:(u/2) u=2 h/tanA=2 h/tan42 =2 6.5/tan42 =2 6.5/0.900404=14.43796  a=u/2=14.438/210.2092 cm  S1=a2=10.20922104.2274 cm2  h2=h2+(a/2)2=6.52+(10.2092/2)28.2648 cm  S2=a h2/2=10.2092 8.2648/242.1884 cm2  S=S1+4 S2=104.2274+4 42.1884=273 cm2
V=13 S1 h=13 104.2274 6.5=225.8 cm3



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Showing 1 comment:
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Peachpie1123
Thank u i was trying to find the answer to that in class(my teacher let us look it up and i said it so i got it right.

23 days ago  1 Like
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