Controller

Output Controller of the company in the control of 50 randomly selected products found that 37 of them had no defect 8 has only one flaw, three had two defects, and two products had three defects. Determine the standard deviation and coefficient of variation.

Result

s =  0.775
c =  1.938

Solution:

m=(37 0+8 1+3 2+2 3)/50=25=0.4 r=(37 (0m)2+8 (1m)2+3 (2m)2+2 (3m)2)/50=(37 (00.4)2+8 (10.4)2+3 (20.4)2+2 (30.4)2)/50=35=0.6 s=r=0.60.77460.775m=(37 \cdot \ 0+8 \cdot \ 1+3 \cdot \ 2+2 \cdot \ 3)/50=\dfrac{ 2 }{ 5 }=0.4 \ \\ r=(37 \cdot \ (0-m)^2+8 \cdot \ (1-m)^2+3 \cdot \ (2-m)^2+2 \cdot \ (3-m)^2)/50=(37 \cdot \ (0-0.4)^2+8 \cdot \ (1-0.4)^2+3 \cdot \ (2-0.4)^2+2 \cdot \ (3-0.4)^2)/50=\dfrac{ 3 }{ 5 }=0.6 \ \\ s=\sqrt{ r }=\sqrt{ 0.6 } \doteq 0.7746 \doteq 0.775
c=s/m=3116=1.938c=s/|m|=\dfrac{ 31 }{ 16 }=1.938



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