Isosceles trapezoid

In an isosceles trapezoid KLMN intersection of the diagonals is marked by the letter S. Calculate the area of trapezoid if /KS/: /SM/ = 2:1 and a triangle KSN is 14 cm2.

Correct result:

S =  63 cm2

Solution:

S1=14 cm2 S2=S1=14=14 cm2 S1=2xv1/2 S3=xv1/2 S3=S1/2=14/2=7 cm2 S1=1 yv2/2 S4=2 yv2/2 S4=yv2=2 S1  S4=2 S1=2 14=28 cm2 S=S1+S2+S3+S4=14+14+7+28=63 cm2



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