A bus

A bus is scheduled to travel a distance of 121 km in 2 3/4 hours. What must the average rate of speed be maintained to arrive on schedule?

Correct answer:

v =  44 km/h

Step-by-step explanation:

s=121 km t=243=2+43=42 4+3=48+3=411=2.75 h  v=s/t=121/411=121:411=121 114=11121 4=11484=44 km/h



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