# Angles of a hexagon

Find the interior angles of a hexagon if the sizes of the angles form an arithmetic sequence and the smallest angle is 70°.

Correct result:

A =  70 °
B =  90 °
C =  110 °
D =  130 °
E =  150 °
F =  170 °

#### Solution:

$A=70=7{0}^{\circ }$
$C=B+d=90+20=11{0}^{\circ }$
$D=C+d=110+20=13{0}^{\circ }$
$E=D+d=130+20=15{0}^{\circ }$

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