Horizontal Cylindrical Segment

How much fuel is in the tank of horizontal cylindrical segment with a length 10m, width of level 1 meter and level is 0.2 meters below the upper side of the tank?

Correct result:

V =  15.1379 m3


a=10 s=1 h=0.2 r2=(s/2)2+(rh)2 r2=0.25+(r0.2)2 r=0.725 H=2 rh=2 0.7250.2=54=1.25 A=r2 arccos((rh)/r)=0.7252 arccos((0.7250.2)/0.725)0.4 B=(rh) 2 r hh2=(0.7250.2) 2 0.725 0.20.22=2180=0.2625 S1=AB=0.40.26250.1375 S2=π r2=3.1416 0.72521.6513 S=S2S1=1.65130.13751.5138 V=S a=1.5138 10=15.1379 m3

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