Sides of triangle

Triangle has a circumference of 42 cm. Side a is two times shorter than side b, and side c is 2 cm longer than side a. Find the sizes of the sides of a triangle.

Correct answer:

a =  16
b =  8
c =  18

Step-by-step explanation:


a+b+c=42
a=2b
c = a+2

a+b+c=42
a=2·b
c = a+2

a+b+c = 42
a-2b = 0
a-c = -2

Row 2 - Row 1 → Row 2
a+b+c = 42
-3b-c = -42
a-c = -2

Row 3 - Row 1 → Row 3
a+b+c = 42
-3b-c = -42
-b-2c = -44

Row 3 - -1/-3 · Row 2 → Row 3
a+b+c = 42
-3b-c = -42
-1.667c = -30


c = -30/-1.66666667 = 18
b = -42+c/-3 = -42+18/-3 = 8
a = 42-b-c = 42-8-18 = 16

a = 16
b = 8
c = 18

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