# Trapezoid

trapezoid ABCD a = 35 m, b=28 m c = 11 m and d = 14 m. How to calculate its area?

Correct result:

S =  321.949 cm2

#### Solution:

$a=35 \ \\ b=28 \ \\ d=14 \ \\ c=11 \ \\ h>0 \ \\ \ \\ d^2=x^2+h^2 \ \\ b^2=y^2+h^2 \ \\ c=a-x-y \ \\ \ \\ 14^2=x^2+h^2 \ \\ 28^2=y^2+h^2 \ \\ c=35-x-y \ \\ \ \\ x=-1/4=- \dfrac{ 1 }{ 4 }=-0.25 \ \\ y=97/4=\dfrac{ 97 }{ 4 }=24.25 \ \\ c=a-x-y=35-(-0.25)-24.25=11 \ \\ \ \\ h=\sqrt{ d^2-x^2 }=\sqrt{ 14^2-(-0.25)^2 } \doteq 13.9978 \ \text{cm} \ \\ S=(a+c) \cdot \ h/2=(35+11) \cdot \ 13.9978/2=321.949 \ \text{cm}^2$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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