How many 9

How much percent volume remains of a sphere if the diameter decrease 3×?

Correct answer:

p =  96.2963 %

Step-by-step explanation:

d = D/3 r = R/3  V1 = 34π r3 V2 = 34π R3  p = 100   V1V1V2  p = 100   R3R3r3  p = 100   R3R3(R/3)3  p = 100   11(1/3)3  p=100 (1(1/3)3)=272600%=96.2963%



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