The sum

The sum of the squares of two immediately following natural numbers is 1201. Find these numbers.

Correct answer:

a =  24
b =  25

Step-by-step explanation:

2x2=1201 x=1201/224.5051 x1=x=24.5051=24 x2=x=24.5051=25  a2+(a+1)2=1201  2a2+2a1200=0 2 ...  prime number 1200=24352 GCD(2,2,1200)=2  a2+a600=0  p=1;q=1;r=600 D=q24pr=1241(600)=2401 D>0  a1,2=2pq±D=21±2401 a1,2=21±49 a1,2=0.5±24.5 a1=24 a2=25  a=a1=24

Our quadratic equation calculator calculates it.

b=a+1=24+1=25



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