# Speed of Slovakian trains

Rudolf decided to take the train from the station 'Trnava' to 'Zemianske Kostoľany'. In the train timetables found train R 725 Remata :

km
0Bratislava hl.st.12:57
19Pezinok13:1213:13
46Trnava13:3013:32
63Leopoldov13:4514:01
68Hlohovec14:0614:07
87Zbehy14:2214:23
114Topoľčany14:4914:50
124Chynorany15:0215:04
131Partizánske15:1415:16
145Zemianske Kostoľany15:3215:33
149Nováky15:3815:39
158Prievidza15:49

Calculate the average speed between these stations, travel distance and time.

Result

s =  99 km
t =  2 h
v =  49.5 km/h

#### Solution:

$s=145-46 = 99 \ \text { km }$
$t=(15-13)+(32-32)/60 = 2 \ \text { h }$
$v=(145-46)/((15-13)+(32-32)/60) = \dfrac{ 99 }{ 2 } = 49.5 \ \text { km/h }$

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