MO SK/CZ Z9–I–3

John had the ball that rolled into the pool and it swam in the water. Its highest point was 2 cm above the surface. Diameter of circle that marked the water level on the surface of the ball was 8 cm. Determine the diameter of John ball.

Result

D =  10 cm

Solution:

r2=(8/2)2+(r2)2 r2=16+r24r+4 0=204r r=20/4=5 cm D=2 r=2 5=10 cmr^2=(8/2)^2+(r-2)^2 \ \\ r^2=16+r^2-4r+4 \ \\ 0=20-4r \ \\ r=20/4=5 \ \text{cm} \ \\ D=2 \cdot \ r=2 \cdot \ 5=10 \ \text{cm}



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I need more explanation as to where these equations are coming from.

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