Modulo

Find x in the modulo equation:

47x = 4 (mod 9)

Hint - read as what number 47x divided by 9 (modulo 9) give remainder 4.

Correct answer:

x =  2

Step-by-step explanation:

47x = 9k + 4; k,xinteger k = (47x4)/9 k1=(47 14)/9=943=4974.7778 k2=(47 24)/9=10 k3=(47 34)/9=9137=159215.2222 k4=(47 44)/9=9184=209420.4444 . x=2



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