Isosceles right triangle

Area of an isosceles right triangle is 18 dm². Calculate the length of its base.

Correct answer:

c =  8.4853 dm

Step-by-step explanation:

$$\begin{gathered} S=18{\text{dm}}^2 \\ S=ab\mathrm{/}2 \\ a=b \\ a=\sqrt{2\cdot S}=\sqrt{2\cdot 18}=6\text{ dm } \\ b=a=6\text{ dm } \\ c=\sqrt{a^2+b^2}=\sqrt{6^2+6^2}=6\sqrt{2}=8.4853\text{ dm} \end{gathered}$$

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