Four sides of trapezoid

In the trapezoid ABCD is |AB| = 73.6 mm; |BC| = 57 mm; |CD| = 60 mm; |AD| = 58.6 mm. Calculate the size of its interior angles.

Correct result:

A =  76.5803 °
B =  90 °
C =  90 °
D =  103.4197 °

Solution:

a=73.6 b=57 c=60 d=58.6 a2=ac=73.660=685=13.6 A1=arccos((d2+a22b2)/(2 d a2))=arccos((58.62+13.62572)/(2 58.6 13.6))1.3366 A=A1=A1 180π=1.3366 180π=76.58=76.5803=763449"
B1=arccos((b2+a22d2)/(2 b a2))=arccos((572+13.6258.62)/(2 57 13.6))1.5708 B=B1=B1 180π=1.5708 180π=90=90
C=180B=18090=90=90
D=180A=18076.5803103.4197=103.4197=1032511" x=A+B+C+D=76.5803+90+90+103.4197=360

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