# Four sides of trapezoid

In the trapezoid ABCD is |AB| = 73.6 mm; |BC| = 57 mm; |CD| = 60 mm; |AD| = 58.6 mm. Calculate the size of its interior angles.

Correct result:

A =  76.5803 °
B =  90 °
C =  90 °
D =  103.4197 °

#### Solution:

$C=180-B=180-90=9{0}^{\circ }=9{0}^{\circ }$

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