# Stones in aquarium

In an aquarium with a length 2 m; width 1.5 m and a depth of 2.5 m is a water level up to three-quarters of the depth. Can we place stones with a volume of 2 m3 into the aquarium without water being poured out?

Result

x =  0

#### Solution:

$a = 2 \ m \ \\ b = 1.5 \ m \ \\ c = 2.5 \ m \ \\ V_{ 1 } = a \cdot \ b \cdot \ c = 2 \cdot \ 1.5 \cdot \ 2.5 = \dfrac{ 15 }{ 2 } = 7.5 \ m^3 \ \\ V_{ 2 } = 3/4 \cdot \ V_{ 1 } = 3/4 \cdot \ 7.5 = \dfrac{ 45 }{ 8 } = 5.625 \ m^3 \ \\ V_{ 3 } = V_{ 2 } + 2 = 5.625 + 2 = \dfrac{ 61 }{ 8 } = 7.625 \ m^3 \ \\ V_{ 3 } > V_{ 1 } \ \\ x = 0$

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