# Movement

From the crossing of two perpendicular roads started two cyclists (each at different road). One runs at average speed 28 km/h, the second at average speed 24 km/h. Determine the distance between them after 45 minutes cycling.

Correct result:

x =  27.659 km

#### Solution:

$t=45 \ min \rightarrow h=45 / 60 \ h=0.75 \ h \ \\ v_{1}=28 \ \text{km/h} \ \\ v_{2}=24 \ \text{km/h} \ \\ \ \\ s_{1}=v_{1} \cdot \ t=28 \cdot \ 0.75=21 \ \text{km} \ \\ s_{2}=v_{2} \cdot \ t=24 \cdot \ 0.75=18 \ \text{km} \ \\ \ \\ x=\sqrt{ s_{1}^2 + s_{2}^2 }=\sqrt{ 21^2 + 18^2 }=3 \ \sqrt{ 85 }=27.659 \ \text{km}$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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