Isosceles trapezoid

Calculate the area of an isosceles trapezoid whose bases are at a ratio of 5:3. The arm is 6cm long and 4cm high.

Correct answer:

S =  71.5542 cm2

Step-by-step explanation:

a:c = 5:3 b=6 cm d=b=6 cm h=4 cm  x=b2h2=6242=2 5 cm4.4721 cm a = x+c+x 3a = 5c 3 (c+2x) = 5c 3c + 6x  = 5c 2c = 6x  c=3 x=3 4.4721=6 5 cm13.4164 cm a=5/3 c=5/3 13.4164=10 5 cm22.3607 cm  S=(a+c) h/2=(22.3607+13.4164) 4/2=32 571.5542 cm2   Verifying Solution:  k1=ca=13.416422.3607=351.6667



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