# Container

The container has a cylindrical shape the base diameter 0.8 m and the area of the base is equal to the area of the wall. How many liters of water can we pour into the container?

Result

V =  100.531 l

#### Solution:

$D = 0.8 \ m \ \\ r = D/2 = 0.8/2 = \dfrac{ 2 }{ 5 } = 0.4 \ m \ \\ S = \pi \cdot \ r^2 = 3.1416 \cdot \ 0.4^2 \doteq 0.5027 \ m^2 \ \\ S = \pi \cdot \ D \cdot \ h \ \\ h = S/(\pi \cdot \ D) = 0.5027/(3.1416 \cdot \ 0.8) = \dfrac{ 1 }{ 5 } = 0.2 \ m \ \\ V_{ 1 } = S \cdot \ h = 0.5027 \cdot \ 0.2 \doteq 0.1005 \ m^3 \ \\ V = 1000 \cdot \ V_{ 1 } = 1000 \cdot \ 0.1005 \doteq 100.531 = 100.531 \ \text { l }$

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