# Beer

After three 10° beers consumed in a short time, there is 5.6 g of alcohol in 6 kg adult human blood. How much is it per mille?

Result

p =  0.9

#### Solution:

$m_{ 1 } = 5.6 \ g = 5.6 / 1000 \ kg = 0.0056 \ kg \ \\ m_{ 2 } = 6 \ kg \ \\ \ \\ p = 1000 \cdot \ \dfrac{ m_{ 1 } }{ m_{ 2 } } = 1000 \cdot \ \dfrac{ 0.0056 }{ 6 } = \dfrac{ 14 }{ 15 } \doteq 0.9333 = 0.9 \ ‰$

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