Motion problem

From Levíc to Košíc go car at speed 81 km/h.
From Košíc to Levíc go another car at speed 69 km/h.

How many minutes before the meeting will be cars 27 km away?

Result

t =  10.8 min

Solution:

v1=81 km/h v2=69 km/h s=27 km  v=v1+v2=81+69=150 km/h t1=sv=27150=950=0.18 h t=t1h=t1 60 h=10.8 h=545=10.8  min v_{ 1 } = 81 \ km/h \ \\ v_{ 2 } = 69 \ km/h \ \\ s = 27 \ km \ \\ \ \\ v = v_{ 1 }+v_{ 2 } = 81+69 = 150 \ km/h \ \\ t_{ 1 } = \dfrac{ s }{ v } = \dfrac{ 27 }{ 150 } = \dfrac{ 9 }{ 50 } = 0.18 \ h \ \\ t = t_{ 1 } \rightarrow h = t_{ 1 } \cdot \ 60 \ h = 10.8 \ h = \dfrac{ 54 }{ 5 } = 10.8 \ \text { min }







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