Motion problem

From Levíc to Košíc go car at speed 81 km/h.
From Košíc to Levíc go another car at speed 69 km/h.

How many minutes before the meeting will be cars 27 km away?

Result

t =  10.8 min

Solution:

v1=81 km/h v2=69 km/h s=27 km  v=v1+v2=81+69=150 km/h t1=sv=27150=950=0.18 h t=t1h=t1 60 h=10.8 h=545=10.8 minv_{1}=81 \ \text{km/h} \ \\ v_{2}=69 \ \text{km/h} \ \\ s=27 \ \text{km} \ \\ \ \\ v=v_{1}+v_{2}=81+69=150 \ \text{km/h} \ \\ t_{1}=\dfrac{ s }{ v }=\dfrac{ 27 }{ 150 }=\dfrac{ 9 }{ 50 }=0.18 \ \text{h} \ \\ t=t_{1} \rightarrow h=t_{1} \cdot \ 60 \ h=10.8 \ h=\dfrac{ 54 }{ 5 }=10.8 \ \text{min}



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