Events

Event U has the probability of 0.89. What is the probability that the event U occurs in 4, 2, 8 try?

Correct answer:

x4 =  0.12 %
x2 =  9.79 %
x8 =  0 %

Step-by-step explanation:

p = 0.89 \ \\ q = 1 - p = 1 - 0.89 = \dfrac{ 11 }{ 100 } = 0.11 \ \\ \ \\ x4 = #%#p = 0.89 \ \\ q = 1 - p \ \\ \ \\ \ \\ x4 = 100 * pow(q, 4-1) * px_{4} = 100 \cdot \ q^{ 4-1 } \cdot \ p = 100 \cdot \ 0.11^{ 4-1 } \cdot \ 0.89 = 0.12 \%
x2 = #%# \ \\ x2 = 100 * pow(q, 2-1) * px_{2} = 100 \cdot \ q^{ 2-1 } \cdot \ p = 100 \cdot \ 0.11^{ 2-1 } \cdot \ 0.89 = 9.79 \%
x8 = #%# \ \\ x8 = 100 * pow(q, 8-1) * px_{8} = 100 \cdot \ q^{ 8-1 } \cdot \ p = 100 \cdot \ 0.11^{ 8-1 } \cdot \ 0.89 = 0 \%



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