# Troops

The route is long 147 km and the first-day first regiment went at an average speed of 12 km/h and journey back 21 km/h. The second day went second regiment the same route at an average speed of 22 km/h there and back.

Which regiment will take route longer?

Result

#### Solution:

$t_1 = \dfrac{ 147}{ 12} + \dfrac{ 147}{ 21} = 19.25 \ h \ \\ t_2 = \dfrac{ 147}{ 22}+ \dfrac{ 147}{ 22} = 13.36 \ h \ \\ \ \\ t_1 > t_2$

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3qne=b=3wn8e b=

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