IS trapezoid

Calculate the length of diagonal u and height v of isosceles trapezoid ABCD, whose bases have lengths a = |AB| = 37 cm, c = |CD| = 29 cm and legs b = d = |BC| = |AD| = 28 cm.

Result

v =  27.7 cm
u=|AC|=|BD| =  43.1 cm

Solution:

a=37 cm c=29 cm r=28 cm x=(a−c)/2=(37−29)/2=4 cm v=r2−x2=282−42≐16 3≐27.7128≐27.7 cma=37 \ \text{cm} \ \\ c=29 \ \text{cm} \ \\ r=28 \ \text{cm} \ \\ x=(a-c)/2=(37-29)/2=4 \ \text{cm} \ \\ v=\sqrt{ r^2-x^2 }=\sqrt{ 28^2-4^2 } \doteq 16 \ \sqrt{ 3 } \doteq 27.7128 \doteq 27.7 \ \text{cm}
u=v2+(a−x)2=27.71282+(37−4)2≐43.0847≐43.1 cmu=\sqrt{ v^2+(a-x)^{ 2 } }=\sqrt{ 27.7128^2+(37-4)^{ 2 } } \doteq 43.0847 \doteq 43.1 \ \text{cm}

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I don’t know how to do it????????

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