IS trapezoid

Calculate the length of diagonal u and height v of isosceles trapezoid ABCD, whose bases have lengths a = |AB| = 37 cm, c = |CD| = 29 cm and legs b = d = |BC| = |AD| = 28 cm.

Result

v =  27.7 cm
u=|AC|=|BD| =  43.1 cm

Solution:

$a = 37 \ cm \ \\ c = 29 \ cm \ \\ r = 28 \ cm \ \\ x = (a-c)/2 = (37-29)/2 = 4 \ cm \ \\ v = \sqrt{ r^2-x^2 } = \sqrt{ 28^2-4^2 } = 16 \ \sqrt{ 3 } \doteq 27.7128 = 27.7 \ \text { cm }$

$u = \sqrt{ v^2+(a-x)^{ 2 } } = \sqrt{ 27.7128^2+(37-4)^{ 2 } } \doteq 43.0847 = 43.1 \ \text { cm }$

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I don’t know how to do it????????

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