Water tank

A 288 hectoliter of water was poured into the tank with dimensions 12 m and 6 m bottom and 2 m depth. What part of the volume of the tank water occupied? Calculate the surface of tank wetted with water.

Correct result:

p =  20 %
A =  86.4 m2

Solution:

a=12 m b=6 m c=2 m S=a b=12 6=72 m2 V=S c=72 2=144 m3 V1=288/10=1445=28.8 m3 p=100 V1/V=100 28.8/144=20=20% c1=V1/S=28.8/72=25=0.4 m
A=S+c1 (2 a+2 b)=72+0.4 (2 12+2 6)=4325=4325 m2=86.4 m2



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Showing 1 comment:
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Jimbob
This question wording make no sense in brainhole.

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