# Vinegar 2

How many percentage of getvinegar solution, if we mix to 3.5 liters of 5.8% and 5 liters of 7.6% vinegar?

Result

x =  6.86 %

#### Solution:

$x_{1}=3.5 \cdot \ \dfrac{ 5.8 }{ 100 } + 5 \cdot \ \dfrac{ 7.6 }{ 100 }=\dfrac{ 583 }{ 1000 }=0.583 \ \text{l} \ \\ V=3.5 + 5=8.5 \ \text{l} \ \\ \ \\ x=100 \cdot \ \dfrac{ x_{1} }{ V }=100 \cdot \ \dfrac{ 0.583 }{ 8.5 } \doteq \dfrac{ 583 }{ 85 } \doteq 6.8588 \doteq 6.86 \%$

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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

Nestor
Solution is wrong.
x=[12(4.3) + 1(3.7)]/ (12+1)=4.25%

Math student
@Nestor the answer is correct. I figured another solution is just to average the concentrations of the solutions as the volume is same.

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