Combinations 6

6 purses
9 flaps
12 straps
Every combination must include 1 purse, 1 flap, and 1 strap. How many are possible combinations?

Result

n =  108

Solution:

n=6 9 123!=108n=\dfrac{ 6 \cdot \ 9 \cdot \ 12 }{ 3! }=108



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Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...):

Showing 3 comments:
#
Math student
I think answer should be 325. Please clarify

#
Matematik
Why is it not right answer 6*9*12?

4 months ago  1 Like
#
Math student
it is 108 because 6*9*12÷3!

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