# Combinations 6

6 purses
9 flaps
12 straps
Every combination must include 1 purse, 1 flap, and 1 strap. How many are possible combinations?

Result

n =  108

#### Solution:

$n=\dfrac{ 6 \cdot \ 9 \cdot \ 12 }{ 3! }=108$

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Math student

Matematik
Why is it not right answer 6*9*12?

4 months ago  1 Like
Math student
it is 108 because 6*9*12÷3!

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