Square JKLM has sides of length 24 cm. Point S is the center of LM. Calculate the area of the quadrant JKSM in cm2.

Correct result:

S =  432 cm2


a=24 cm S1=a2=242=576 cm2  S2=a (a/2)/2=24 (24/2)/2=144 cm2  S=S1S2=576144=432 cm2a=24 \ \text{cm} \ \\ S_{1}=a^2=24^2=576 \ \text{cm}^2 \ \\ \ \\ S_{2}=a \cdot \ (a/2) / 2=24 \cdot \ (24/2) / 2=144 \ \text{cm}^2 \ \\ \ \\ S=S_{1}-S_{2}=576-144=432 \ \text{cm}^2

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