Circle chord

What is the length d of the chord circle of diameter 50 dm, if the distance from the center circle is 21 dm?

Result

x =  54.259 dm

Solution:

D=50 dm t=21 dm  r=D/2=50/2=25 dm  (x/2)2=r2t2  x=4 r2t2=4 252212=8 4654.2586=54.259  dm D = 50 \ dm \ \\ t = 21 \ dm \ \\ \ \\ r = D/2 = 50/2 = 25 \ dm \ \\ \ \\ (x/2)^2 = r^2 - t^2 \ \\ \ \\ x = 4 \cdot \ \sqrt{ r^2-t^2 } = 4 \cdot \ \sqrt{ 25^2-21^2 } = 8 \ \sqrt{ 46 } \doteq 54.2586 = 54.259 \ \text { dm }







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Pythagorean theorem is the base for the right triangle calculator. See also our trigonometric triangle calculator.

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