# Performance

Two masons with the same performance would have made of plaster for 6 days. One of them, however, has increased its daily performance by 50%. How long would take they now to make plaster together?

Result

t =  4 d

#### Solution:

$a = 2 \cdot \ 6 = 12 \ d \ \\ b = 2 \cdot \ 6 = 12 \ d \ \\ b_{ 1 } = b - \dfrac{ 50 }{ 100 } \cdot \ b = 12 - \dfrac{ 50 }{ 100 } \cdot \ 12 = 6 \ d \ \\ \ \\ t = \dfrac{ 1 }{ 1/a + 1/b_{ 1 } } = \dfrac{ 1 }{ 1/12 + 1/6 } = 4 = 4 \ \text{ d }$

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