# Cube walls

Find the volume and the surface area of the cube if the area of one of its walls is 40 cm2.

Result

V =  252.982 cm3
S =  240 cm2

#### Solution:

$S_{ 1 } = 40 \ cm^2 \ \\ a = \sqrt{ S_{ 1 } } = \sqrt{ 40 } = 2 \ \sqrt{ 10 } \ cm \doteq 6.3246 \ cm \ \\ \ \\ V = a^3 = 6.3246^3 = 80 \ \sqrt{ 10 } \doteq 252.9822 = 252.982 \ cm^3$
$S = 6 \cdot \ S_{ 1 } = 6 \cdot \ 40 = 240 = 240 \ cm^2$

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