Vinegar mixing

We mix 70g water and 50g 8% vinegar. How many percents of the solution of vinegar we produce?

Correct result:

p =  3.333 %

Solution:

$m_{1}=70 \ \text{g} \ \\ m_{2}=50 \ \text{g} \ \\ \ \\ v=0.08 \cdot \ m_{2}=0.08 \cdot \ 50=4 \ \text{g} \ \\ \ \\ p=100 \cdot \ \dfrac{ v }{ m_{1}+m_{2} }=100 \cdot \ \dfrac{ 4 }{ 70+50 }=\dfrac{ 10 }{ 3 }=3.333 \%$

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