Regular triangular pyramid

Calculate the volume and surface area of the regular triangular pyramid and the height of the pyramid is 12 centimeters, the bottom edge has 4 centimeters and the height of the side wall is 12 centimeters

Result

V =  96 cm3
S =  96 cm2

Solution:

h=12 cm a=4 cm h2=12 cm  S1=a h2/2=4 12/2=24 cm2  V=13 S1 h=13 24 12=96=96 cm3h = 12 \ cm \ \\ a = 4 \ cm \ \\ h_{ 2 } = 12 \ cm \ \\ \ \\ S_{ 1 } = a \cdot \ h_{ 2 }/2 = 4 \cdot \ 12/2 = 24 \ cm^2 \ \\ \ \\ V = \dfrac{ 1 }{ 3 } \cdot \ S_{ 1 } \cdot \ h = \dfrac{ 1 }{ 3 } \cdot \ 24 \cdot \ 12 = 96 = 96 \ cm^3
S=4 S1=4 24=96=96 cm2S = 4 \cdot \ S_{ 1 } = 4 \cdot \ 24 = 96 = 96 \ cm^2



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