# Constant motion

The car has undergone constant motion 120 km in 1 hour 30 minutes. Determine its average speed. Determine how long car drove in the first 20 minutes and 50 minutes from the start of the move.

Result

v =  80 km/h
s1 =  26.667 km
s2 =  66.667 km

#### Solution:

$s = 120 \ km \ \\ t = 1 + 30/60 = \dfrac{ 3 }{ 2 } = 1.5 \ h \ \\ \ \\ v = s/t = 120/1.5 = 80 = 80 \ \text{ km/h }$
$t_{ 1 } = 20 \ min = 20 / 60 \ h = 0.33333333333333 \ h \ \\ s_{ 1 } = v \cdot \ t_{ 1 } = 80 \cdot \ 0.3333 = \dfrac{ 80 }{ 3 } \doteq 26.6667 = 26.667 \ \text{ km }$
$t_{ 2 } = 50 \ min = 50 / 60 \ h = 0.83333333333333 \ h \ \\ s_{ 2 } = v \cdot \ t_{ 2 } = 80 \cdot \ 0.8333 = \dfrac{ 200 }{ 3 } \doteq 66.6667 = 66.667 \ \text{ km }$

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