# Athletic competition

In a 400 meter athletic competition, a participant covers the distance as given below.
find the average speed?

first 80 meters 10 m/s
next 240 meters 7.5 m/s
last 80 meters 10 m/s

Result

v =  8.333 m/s

#### Solution:

$s=vt \ \\ s_{1}=80 \ \text{m} \ \\ s_{2}=240 \ \text{m} \ \\ s_{3}=80 \ \text{m} \ \\ \ \\ v_{1}=10 \ \text{m/s} \ \\ v_{2}=7.5 \ \text{m/s} \ \\ v_{3}=10 \ \text{m/s} \ \\ \ \\ t_{1}=s_{1}/v_{1}=80/10=8 \ \text{s} \ \\ t_{2}=s_{2}/v_{2}=240/7.5=32 \ \text{s} \ \\ t_{3}=s_{3}/v_{3}=80/10=8 \ \text{s} \ \\ \ \\ v=\dfrac{ s_{1}+s_{2}+s_{3} }{ t_{1}+t_{2}+t_{3} }=\dfrac{ 80+240+80 }{ 8+32+8 } \doteq \dfrac{ 25 }{ 3 } \doteq 8.3333 \doteq 8.333 \ \text{m/s}$

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