# Tereza

The cube has area of base 256 mm2.

Calculate the edge length, volume and area of its surface.

Result

a =  16 mm
V =  4096 mm3
S2 =  1536 mm2

#### Solution:

$S = 256 \ mm^2 \ \\ S = a^2 = a \cdot \ a \ \\ a = \sqrt{ S } = \sqrt{ 256 } = 16 = 16 \ \text { mm }$
$V = S \cdot \ a = 256 \cdot \ 16 = 4096 = 4096 \ mm^3$
$S_{ 2 } = 6 \cdot \ S = 6 \cdot \ 256 = 1536 = 1536 \ mm^2$

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Nice but boring

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