Uphill and downhill

The cyclist moves uphill at a constant speed of v1 = 10 km/h. When he reaches the top of the hill, he turns and passes the same track downhill at a speed of v2 = 40 km/h. What is the average speed of a cyclist?

Correct answer:

v =  16 km/h

Step-by-step explanation:

v1=10 km/h v2=40 km/h  s = v1 t1 = v2 t2  t2 = v2v1   t1  v = t1+t2s+s =  t1+t2v1 t1+v2 t2  v =  t1+v2v1   t1v1 t1+v2 v2v1   t1  v =  1+v2v1v1+v2 v2v1  v =  1+v2v1v1+v1  v=v2+v12 v1 v2=40+102 10 40=16 km/h



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