# Medians 2:1

Median to side b (tb) in triangle ABC is 12 cm long.
a. What is the distance of the center of gravity T from the vertex B?
b, Find the distance between T and the side b.

Result

x =  8 cm
y =  4 cm

#### Solution:

$t=12 \ \text{cm} \ \\ x=\dfrac{ 2 }{ 3 } \cdot \ t=\dfrac{ 2 }{ 3 } \cdot \ 12=8 \ \text{cm}$
$y=t-x=12-8=4 \ \text{cm}$

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