The diagram 2

The diagram shows a cone with slant height 10.5cm. If the curved surface area of the cone is 115.5 cm2. Calculate correct to 3 significant figures:

*Base Radius
*Volume of the cone


r =  3.501 cm
h =  9.899 cm
V =  127.059 cm3


s=10.5 cm S1=115.5 cm2  S1=π r s  r=S1π s=115.53.1416 10.53.50143.501 cms=10.5 \ \text{cm} \ \\ S_{1}=115.5 \ \text{cm}^2 \ \\ \ \\ S_{1}=\pi \cdot \ r \cdot \ s \ \\ \ \\ r=\dfrac{ S_{1} }{ \pi \cdot \ s }=\dfrac{ 115.5 }{ 3.1416 \cdot \ 10.5 } \doteq 3.5014 \doteq 3.501 \ \text{cm}
s2=h2+r2  h=s2r2=10.523.501429.89919.899 cms^2=h^2 + r^2 \ \\ \ \\ h=\sqrt{ s^2-r^2 }=\sqrt{ 10.5^2-3.5014^2 } \doteq 9.8991 \doteq 9.899 \ \text{cm}
S2=π r2=3.1416 3.5014238.5065 cm2  V=13 S2 h=13 38.5065 9.8991127.0586127.059 cm3S_{2}=\pi \cdot \ r^2=3.1416 \cdot \ 3.5014^2 \doteq 38.5065 \ \text{cm}^2 \ \\ \ \\ V=\dfrac{ 1 }{ 3 } \cdot \ S_{2} \cdot \ h=\dfrac{ 1 }{ 3 } \cdot \ 38.5065 \cdot \ 9.8991 \doteq 127.0586 \doteq 127.059 \ \text{cm}^3

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