# Probability of intersection

Three students have a probability of 0.7,0.5 and 0.4 to graduated from university respectively. What is the probability that at least one of them will be graduated?

Correct result:

p =  0.91

#### Solution:

$p_{1}=0.7 \ \\ p_{2}=0.5 \ \\ p_{3}=0.4 \ \\ \ \\ p=p_{1}+p_{2}+p_{3} - p_{1} \cdot \ p_{2}-p_{2} \cdot \ p_{3}-p_{3} \cdot \ p_{1} + p_{1} \cdot \ p_{2} \cdot \ p_{3}=0.7+0.5+0.4 - 0.7 \cdot \ 0.5-0.5 \cdot \ 0.4-0.4 \cdot \ 0.7 + 0.7 \cdot \ 0.5 \cdot \ 0.4=\dfrac{ 91 }{ 100 }=0.91$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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