Perimeter of RT

Find the circumference of the rectangular triangle if the sum of its legs is 22.5 cm and its area is 62.5 cm2.

Correct answer:

o =  38.5078 cm

Step-by-step explanation:

a+b = 22.5  cm S=62.5 cm2  S = 2ab S = 2a(22.5a)  2 62.5=a (22.5a)  2 62.5=a (22.5a) a222.5a+125=0  p=1;q=22.5;r=125 D=q24pr=22.5241125=6.25 D>0  a1,2=2pq±D=222.5±6.25 a1,2=11.25±1.25 a1=12.5 a2=10  a=a1=12.5=225=12.5 cm b=22.5a=22.512.5=10 cm c=a2+b2=12.52+10216.0078 cm  o=a+b+c=12.5+10+16.0078=38.5078 cm

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